Q. Solve to find the value of the variable: x - 2 = -5

Q. 

Keep ‘x’ variable on Left Hand Side.

Send ‘(-2)’ to the Right Hand Side.

Aim is to keep variable ‘x’ on one side and to send the number values to the other side.

⇒ x = -5 + 2

⇒ x = -3

∴ Value of ‘x’ is found to be ‘-3’

(We first write ‘-5’ previous resident, out of respect)

Now, How is ‘2’ connected to the rest of the expression in the LHS?
By Subtraction operation

∴ Change sign & send to the other side.

-2 → +2

(changed sign of 2)

Q. Solve to find the value of the variable: x - 7 = 10

Q. Solve : Keep variable x on left hand side Send ‘-7’ to the right hand side Aim: To keep variable on one side of the equation and to send number values to the other side. => x = 10 + 7 => x = 17 (we write the previous resident on RHS first, out of respect) Value of variable x is found to be 17 Now, How is ‘7’ connected to the rest of the expression on the LHS? By subtraction operation Change sign & send to other side ‘-7’ -> ‘+7’ (sign of -7 changed)

Q. Solve to find the value of the variable: x + 3 = 12

Q.. Solve for x. on LHS send to RHS Aim is to keep x on 1 side and to send numerical values to other side. => x = 12 - 3 => x = 9 (we write the previous resident on RHS first, and then send the new number to RHS) Value of variable ‘x’ is found to be 9 Now, How is 3 connected to the rest of the expression in LHS? By addition operation Change sign & send to other side ‘+3’ -> ‘-3’ (sign of 3 is changed)

Q. Solve to find the value of the variable:  x - 3 = 5

Q. Solve. Aim is to keep variable ‘x’ on one side (LHS) & send number value ‘-3’ to RHS (other side). => x = 5 + 3 => x = 8 (we write the previous resident present on the other side before sending new number) Value of x variable is found to be 8 Now, 3 is connected to rest of expression on the LHS by subtraction operation Change sign & send to other side. ‘-3’ -> ‘+3’ (Sign of 3 is changed)

Q. Solve to find the value of the variable: x + 9 = 13

Q. keep on Left hand side Send to Right Hand Side. Aim is to keep variable on one side of ‘=’ sign & send numbers to the other side. => x = 13 - 9 => x = 4 (We write the previous resident first before sending to other side, the new number) Value of x variable is found to be 4 Now, How is ‘9’ connected to the rest of the expression on the Left Hand Side? By addition operation Change sign & send to other side ‘+9’ -> ‘-9’ (Sign changed for 9)

Q. Solve to find the value of the variable: x - 3/5 = 7/5 

Q. Keep on LHS Send to Right Hand Side Aim is to keep variable ‘x’ on one side of equation (=) and send numeric value to the other side of equation (=). => x = 7/5 + 3/5 => x = (7+3)/5 => x = 10/5 => x = 2 (We first write the previous resident on the RHS, before sending new number) x variable is found to have a value of 2 Now, 3/5 is connected to the rest of the expression on LHS by subtraction operation Change sign & send to other side -3/5 -> 3/5

Q. Solve to find the value of the variable: x - 1/3 = 2/3

Q. Keep here on LHS Send to RHS Aim is to keep variable to one side of the equation & send numbers to the other side. => x = 2/3 + 1/3 => x = 3/3 => x = 1 (We write the previous resident of the other side, before sending the new number there) Value of x is 1 Now, 1/3 is connected to the rest of the expression on LHS by subtraction operation Change sign & send to other side. -1/3 -> +1/3 (Sign of 1/3 is changed)

Q. Solve to find the value of the variable: x + 1/2 = 7/2

Q. Keep on Left Hand Side (LHS) Send to RHS Aim is to send number parts to other side of “=” and to keep variable x on one side. => x = 7/2 - 1/2 => x = (7 - 1)/2 => x = 6/2 => x = 3 (We write the previous resident of the other side first, then we send the new number) Value of variable x is found to be 3 Now, 1/2 is connected to the rest of the expression on LHS by addition operation Change sign & send to other side. +1/2 -> -1/2 (Sign of 1/2 is changed)