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LINEAR EQUATIONS IN 1 VARIABLE TYPE 4 GAME (A)
LINEAR EQUATIONS IN 1 VARIABLE TYPE 4 GAME (A)
Linear equations in 1 variable multistep addition, subtraction, multiplication and/or division operation transition to 2 steps
Linear equations in 1 variable multistep addition, subtraction, multiplication and/or division operation transition to 2 steps
LINEAR EQUATIONS IN 1 VARIABLE TYPE 4 GAME (B)
LINEAR EQUATIONS IN 1 VARIABLE TYPE 4 GAME (B)
Linear equations in 1 variable multistep addition, subtraction, multiplication and/or division operation transition to 2 steps (no fraction)
Linear equations in 1 variable multistep addition, subtraction, multiplication and/or division operation transition to 2 steps (no fraction)
LINEAR EQUATIONS IN 1 VARIABLE TYPE 4 GAME (C)
LINEAR EQUATIONS IN 1 VARIABLE TYPE 4 GAME (C)
Linear equations in 1 variable multistep addition, subtraction, multiplication and/or division operation transition to 2 steps (no fraction, more detailed steps)
Linear equations in 1 variable multistep addition, subtraction, multiplication and/or division operation transition to 2 steps (no fraction, more detailed steps)
LINEAR EQUATIONS IN 1 VARIABLE TYPE 4 GAME (D)
LINEAR EQUATIONS IN 1 VARIABLE TYPE 4 GAME (D)
Linear equations in 1 variable multistep addition, subtraction, multiplication and/or division operation transition to 2 steps (no fraction, more detailed steps, integer coefficients included, subtraction without brackets included)
Linear equations in 1 variable multistep addition, subtraction, multiplication and/or division operation transition to 2 steps (no fraction, more detailed steps, integer coefficients included, subtraction without brackets included)
Q. Solve to find the value of the variable:
Q. Solve to find the value of the variable:
Q. x - 2 = -5
Keep ‘x’ variable on Left Hand Side.
Send ‘(-2)’ to the Right Hand Side.
Aim is to keep variable ‘x’ on one side and to send the number values to the other side.
⇒ x = -5 + 2
⇒ x = -3
∴ Value of ‘x’ is found to be ‘-3’
(We first write ‘-5’ previous resident, out of respect)
Now, How is ‘2’ connected to the rest of the expression in the LHS?
By Subtraction operation
∴ Change sign & send to the other side.
-2 → +2
(changed sign of 2)
Q. Solve to find the value of the variable:
Q. Solve to find the value of the variable:
Q. x - 2 = -5
Keep ‘x’ variable on Left Hand Side.
Send ‘(-2)’ to the Right Hand Side.
Aim is to keep variable ‘x’ on one side and to send the number values to the other side.
⇒ x = -5 + 2
⇒ x = -3
∴ Value of ‘x’ is found to be ‘-3’
(We first write ‘-5’ previous resident, out of respect)
Now, How is ‘2’ connected to the rest of the expression in the LHS?
By Subtraction operation
∴ Change sign & send to the other side.
-2 → +2
(changed sign of 2)
Q. Solve to find the value of the variable:
Q. Solve to find the value of the variable:
Q. x - 2 = -5
Keep ‘x’ variable on Left Hand Side.
Send ‘(-2)’ to the Right Hand Side.
Aim is to keep variable ‘x’ on one side and to send the number values to the other side.
⇒ x = -5 + 2
⇒ x = -3
∴ Value of ‘x’ is found to be ‘-3’
(We first write ‘-5’ previous resident, out of respect)
Now, How is ‘2’ connected to the rest of the expression in the LHS?
By Subtraction operation
∴ Change sign & send to the other side.
-2 → +2
(changed sign of 2)
Q. Solve to find the value of the variable:
Q. Solve to find the value of the variable:
Q. x - 2 = -5
Keep ‘x’ variable on Left Hand Side.
Send ‘(-2)’ to the Right Hand Side.
Aim is to keep variable ‘x’ on one side and to send the number values to the other side.
⇒ x = -5 + 2
⇒ x = -3
∴ Value of ‘x’ is found to be ‘-3’
(We first write ‘-5’ previous resident, out of respect)
Now, How is ‘2’ connected to the rest of the expression in the LHS?
By Subtraction operation
∴ Change sign & send to the other side.
-2 → +2
(changed sign of 2)
Q. Solve to find the value of the variable:
Q. Solve to find the value of the variable:
Q. x - 2 = -5
Keep ‘x’ variable on Left Hand Side.
Send ‘(-2)’ to the Right Hand Side.
Aim is to keep variable ‘x’ on one side and to send the number values to the other side.
⇒ x = -5 + 2
⇒ x = -3
∴ Value of ‘x’ is found to be ‘-3’
(We first write ‘-5’ previous resident, out of respect)
Now, How is ‘2’ connected to the rest of the expression in the LHS?
By Subtraction operation
∴ Change sign & send to the other side.
-2 → +2
(changed sign of 2)
Q. Solve to find the value of the variable:
Q. Solve to find the value of the variable:
Q. x - 2 = -5
Keep ‘x’ variable on Left Hand Side.
Send ‘(-2)’ to the Right Hand Side.
Aim is to keep variable ‘x’ on one side and to send the number values to the other side.
⇒ x = -5 + 2
⇒ x = -3
∴ Value of ‘x’ is found to be ‘-3’
(We first write ‘-5’ previous resident, out of respect)
Now, How is ‘2’ connected to the rest of the expression in the LHS?
By Subtraction operation
∴ Change sign & send to the other side.
-2 → +2
(changed sign of 2)
Q. Solve to find the value of the variable:
Q. Solve to find the value of the variable:
Q. x - 2 = -5
Keep ‘x’ variable on Left Hand Side.
Send ‘(-2)’ to the Right Hand Side.
Aim is to keep variable ‘x’ on one side and to send the number values to the other side.
⇒ x = -5 + 2
⇒ x = -3
∴ Value of ‘x’ is found to be ‘-3’
(We first write ‘-5’ previous resident, out of respect)
Now, How is ‘2’ connected to the rest of the expression in the LHS?
By Subtraction operation
∴ Change sign & send to the other side.
-2 → +2
(changed sign of 2)
Q. Solve to find the value of the variable:
Q. Solve to find the value of the variable:
Q. x - 2 = -5
Keep ‘x’ variable on Left Hand Side.
Send ‘(-2)’ to the Right Hand Side.
Aim is to keep variable ‘x’ on one side and to send the number values to the other side.
⇒ x = -5 + 2
⇒ x = -3
∴ Value of ‘x’ is found to be ‘-3’
(We first write ‘-5’ previous resident, out of respect)
Now, How is ‘2’ connected to the rest of the expression in the LHS?
By Subtraction operation
∴ Change sign & send to the other side.
-2 → +2
(changed sign of 2)
Q. Solve to find the value of the variable:
Q. Solve to find the value of the variable:
Q. x - 2 = -5
Keep ‘x’ variable on Left Hand Side.
Send ‘(-2)’ to the Right Hand Side.
Aim is to keep variable ‘x’ on one side and to send the number values to the other side.
⇒ x = -5 + 2
⇒ x = -3
∴ Value of ‘x’ is found to be ‘-3’
(We first write ‘-5’ previous resident, out of respect)
Now, How is ‘2’ connected to the rest of the expression in the LHS?
By Subtraction operation
∴ Change sign & send to the other side.
-2 → +2
(changed sign of 2)
Q. Solve to find the value of the variable:
Q. Solve to find the value of the variable:
Q. x - 2 = -5
Keep ‘x’ variable on Left Hand Side.
Send ‘(-2)’ to the Right Hand Side.
Aim is to keep variable ‘x’ on one side and to send the number values to the other side.
⇒ x = -5 + 2
⇒ x = -3
∴ Value of ‘x’ is found to be ‘-3’
(We first write ‘-5’ previous resident, out of respect)
Now, How is ‘2’ connected to the rest of the expression in the LHS?
By Subtraction operation
∴ Change sign & send to the other side.
-2 → +2
(changed sign of 2)
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